prove the third law of logarithm
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Ioga(Mn) = n Ioga(M)
Let loga(Mn) = x ⇒
a^x = M^n
and loga(M) = y
⇒ a^y = M
Now,
a^x = M^n = (a^y)^n = a^(ny)
Therefore, x = ny or,
loga M^n = n loga M [putting the values of x and y].
Let loga(Mn) = x ⇒
a^x = M^n
and loga(M) = y
⇒ a^y = M
Now,
a^x = M^n = (a^y)^n = a^(ny)
Therefore, x = ny or,
loga M^n = n loga M [putting the values of x and y].
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1
Answer:
it is proved above...........
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