prove the traingle abc is right angled
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Step-by-step explanation:
by pythagoras theorem in ΔABD
AB^2=BD^2+AD^2
AB^2=27^2+36^2
AB^2=729+1296
AB=√2025
AB=45cm
Similarly in ΔBDC
BC^2=BD^2+DC^2
BC^2=36^2+48^2
BC^2=1296+2304
BC=√3600
BC=60cm
Now in ΔABC
AC^2=AB^2+BC^2
75^2=45^2+60^2
5625=2025+3600
5625=5625
LHS=RHS
Hence,ΔABC is a right angled triangle
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