Prove the trigonometric identity:
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ANSWER :
_________
( 1 - Sin² α ) sec² α = 1
L. H. S. = ( 1 - Sin² α ) sec ² α
IDENTITY USED :
_______________
[ sin² α + cos² α = 1 ]
[ cos² α = 1 - sin² α ]
=> ( cos ² α ) sec² α
=> cos² α × 1 / Cos² α
=> 1.
_________
( 1 - Sin² α ) sec² α = 1
L. H. S. = ( 1 - Sin² α ) sec ² α
IDENTITY USED :
_______________
[ sin² α + cos² α = 1 ]
[ cos² α = 1 - sin² α ]
=> ( cos ² α ) sec² α
=> cos² α × 1 / Cos² α
=> 1.
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