Prove the |vector A×vector B |whole square + |A•B|whole square =(AB) whole square
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Explanation:
I A×B I = ABsin∅
I A.B I = ABcos∅
so, I A×B I² + I A.B I² = AB²COS²∅ + AB²SIN²∅
= AB²(SIN²∅+COS²∅)
= AB²(1)
= AB² ---- hence proved
hope it might help you
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