Prove theorem 9.2 of class 9
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If two triangles have the same base, and are between same parallel lines, their area will be equal
Step-by-step explanation:
theorem 9.2 of class 9
If two triangles have the same base, and are between same parallel lines, their area will be equal
Let say ΔABC & ΔABD are triangle
Same base AB
CD ║ AB
now let draw perpendicular from C & D at AB
CM⊥AB & DN⊥AN
as AB ║ CD
=> CM = DN
Area of ΔABC = (1/2) AB * CM
Area of ΔABD = (1/2) AB * DN
CM = DN
=> (1/2) AB * CM = (1/2) AB * DN
=> Area of ΔABC = Area of ΔABD
QED
Proved
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