Prove Theorem
In a right angle triangle, the square of the hypotenuse is equal to the sum of the square of remaining sides.
Answers
Answer:
Assume a rt. triangle ABC right angled at B
Draw BD perpendicular to AC
Now, triangle ADB and triangle ABC are similar
So, AD/AB = AB/AC
By cross multiplication AC×AD = AB²
Similarly, CA×DC = BC²
By adding both equations-
AC×AD + CA×DC = AB²+ BC²
AC(AD + DC) = AB² + BC²
AC²=AB² + BC²
Suggestion: It'll be easier to understand if you draw a figure and follow the steps
Step-by-step explanation:
Answer:
Statement: In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the remaining two sides.
To understand it better we break down the statement.
A right-angled triangle is a triangle with a 90-degree angle.
The hypotenuse is the longest side of the right-angled triangle.
The remaining sides of the triangle are called the base and the perpendicular.
Step-by-step explanation:
the diagram above,
∠ABC is a right angle.
AC is the hypotenuse.
AB is known as the perpendicular.
BC is the base.
So according to the Pythagoras Theorem,
(AC)²=(AB)²+(BC)²
