Question

Prove these two triangles ABC and DEF are congruent and also name the 2 congruence condition.​

Answer 1

Step-by-step explanation:

in ∆ABC and∆FDE

<ABC = <DEF (each 90°)

BC = DE (given)

<BAC = <FDE( given )

so that ,

∆ABC=∆FDE (by ASA congruence rule)

Answer 2

Answer:

$< bc = de \\ <abc = fed \\ < df = ac \\ so \: by \: angle \: side \: angle \: it \: is \: congruent$