Question

prove third equation of motion graphically plz

Answer 1

Answer is in Attachment !

Answer 2

your graph is in the form of attachment!

Here, Area of rectangle
= b × h
= ut

Total area = ut + Area of triangle
= ut + ½ (b×h)
= ut + {½ × t × (v-u)}

now from previous (1st equation) equation,

$\frac{v - u}{a} = t$
$v - u = at$

so,

S = ut + {½ × t × (v-u)}
S = ut + ( ½ × t × at)

S = ut + ½ × at²

therefore, S = ut + ½ at² ........ 2nd equation of motion!

then, from 2nd equation of motion,

S = ut + ½ at²

$s = \frac{v - u}{a} + {\frac{1}{2} a (\frac{v - u}{a} )}^{2}$

Thus, v² - u² = 2as ............ HENCE PROVED THE 3RD EQUATION OF MOTION!