Prove this:-(1 + tan^A) cot A/cosec^A= tan A
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soln refers to the attachment
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sec²a-tan²a = 1
sec²a = 1+tan²a
and,
cota = cosa/sina
cosec²a = 1/sin²a
using all these values in question we get ,
(1 + tan^A) cot A/cosec^A= tan A
= sec²a*(cosa/sina)/(1/sin²a)
= seca*sin²a/sina
= seca*sina
= sina/cosa
= tana (Proved)
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