Question

Prove this.........​

Answer 1

Answer:

$\displaystyle\lim_{x\rightarrow\infty}\frac{ae^x+be^{-x}}{ce^x+de^{-x}}\\\\=\lim_{x\rightarrow\infty}\frac{(ae^x+be^{-x})\times e^{-x}}{(ce^x+de^{-x})\times e^{-x}}\\\\=\lim_{x\rightarrow\infty}\frac{a+be^{-2x}}{c+de^{-2x}}\\\\=\frac{a+0}{c+0}\qquad\qquad\text{(since e^{-2x}\rightarrow 0 as x\rightarrow\infty )}\\\\=\frac{a}{c}$

Answer 2

Answer:

subject name

Step-by-step explanation:

The answer is here,

Given that,

= > \: \frac{a + ib}{c + id} = p + iq

We can replace the " i " as " -i ".

= > \frac{a - ib}{c - id} = p - iq