Question

Prove this .
Answer fast... It's urgent​

Answer 1

Answer:

1/(3+√7)+1/(√7+√5)+1/(√5+√3)+1/(√3+1)

=1/(3+√7)×(3-√7)/(3-√7)+1/(√7+√5)×(√7-√5)/(√7-√5)+1/(√5+√3)×(√5-√3)/(√5-√3)+1/(√3+1)× (√3-1)/(√3-1)

=(3-√7)/(3^2-√7^2)+(√7-√5)/(√7^2-√5^2)+(√5-√3)/(√5^2-√3^2)+(√3-1)/(√3^2-1^2)

=3-√7)/(9-7)+(√7-√5)/(7-5)+(√5-√3)/(5-3)+(√3-1)/(3-1)

=3-√7+√7-√5+√5-√3+√3-1/2

=3-1/2

=2/2

=1

therefore L.H.S=R.H S

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