Prove this both sums
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2 ans) given ABCD is rectangle....
AC is diagonal......
so,AB =CD
AD=BC
AC=AC.....therefore,ABC is congruent toADC
AC is diagonal......
so,AB =CD
AD=BC
AC=AC.....therefore,ABC is congruent toADC
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1) in ΔXYZ and ΔABC,
XZ = AC (both 8 cm)
YZ = AB (both 6 cm)
XY = BC(both 7cm)
thus,
ΔXYZ is congruent to ΔABC, by SSS congruence rule as three sides are equal
2)in ΔABC and ΔADC,
DC = AB ( opp.sides of rectangles are equal)
AD = BC (opp.sides of rectangles are equal)
AC= AC (diagnol common to both)
so ΔABC is congruent to ΔADC, by SSS congruence rule as three sides are equal.
hope it helps!!!
XZ = AC (both 8 cm)
YZ = AB (both 6 cm)
XY = BC(both 7cm)
thus,
ΔXYZ is congruent to ΔABC, by SSS congruence rule as three sides are equal
2)in ΔABC and ΔADC,
DC = AB ( opp.sides of rectangles are equal)
AD = BC (opp.sides of rectangles are equal)
AC= AC (diagnol common to both)
so ΔABC is congruent to ΔADC, by SSS congruence rule as three sides are equal.
hope it helps!!!
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