prove this by using principal of mathematical induction for all n€N
19. n(n + 1) (n + 5) is a multiple of 3.
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Let P(n): n(n + 1)(n + 5) is a multiple of 3.
For n = 1, the given expression becomes (1 × 2 × 6) = 12, which is a multiple of 3.
So, the given statement is true for n = 1, i.e. P(1) is true. ... Hence, by the principle of mathematical induction,
P(n) is true for all n ∈ N.
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