Prove this concept
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First we have to prove that
(i)∆ABC=∆DBC
according to the picture
AB=DC(given in the question)
<A=<D(given in the question)
BC=BC(common side)
hence proved that
∆ABC=∆DBC
(ii)<B=<C
we have recall the theory that is:
The angles opposite to the equal sides are also equal
here=angle b opposite side is DC
angle c opposite side is AB
AB and DC are equal sides,it is givenin the question
hence proved that
<B=<C
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