Question

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Answer 1

Explanation:

here is ur answer

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Answer 2

Hi mate

Here is ur answer ✔

$\bf\bold{\pink{Given}}$

$\sf \: if \: x + iy = (a + ib)^{2} . \: find \: the \: value \: of \: {x}^{2} and {y}^{2}$

$\bf\bold{\pink{Answer}}$

$\sf{\green}if \: x + iy = \frac{a + ib}{a - ib}. \: prove \: that \: {x +}^{2} + {y}^{2} = 1$

$\sf{\green}(x + iy)( x- iy) = ( \frac{a + ib}{a - ib} )( \frac{a - ib}{a + ib} )$

$\boxed{\sf {x}^{2} + {y}^{2} = \frac{ {a}^{2} + {b}^{2} }{ {a}^{2} + {b}^{2} } }$

$\sf{\green}hence \: proved$