Question

Prove this equation.​

Answer 1

Step-by-step explanation:

We have,

$\rm \dfrac{\sin A}{ \sin (90^{\circ} -A)} + \dfrac{\cos A}{\cos (90^{\circ} -A)}$

We know that,

$\boxed{ \sin (90^{\circ}- θ)= \cos θ}$

$\boxed{ \cos (90^{\circ}- θ)= \sin θ}$

$\rm \dfrac{\sin A}{ \cos A} + \dfrac{\cos A}{\sin A}$

$\rm \dfrac{\sin ^2 A+ \cos ^2A}{ \cos A \sin A}$

We know that,

$\boxed{ \rm \sin ^2 θ + \cos ^2 θ =1}$

$\rm \dfrac{1}{ \cos A \sin A}$

$\rm \dfrac{1}{ \cos A } · \dfrac{1}{\sin A}$

$\rm = \sec A \cosec A$

$\rm \qquad \qquad Henced, proved$

Answer 2

Answer:

Done... (⌒o⌒)

best of luck for ur board term 1 exam... mate ʕ•ﻌ•ʔ