Question

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Answer 1

#askgoodquestion #here'stheanswer

identities used here are,

$\frac{ \sin(e) }{ \cos(e) } = \tan(e)$

and

${ \sin (e ) \: }^{2} - { \cos(e) }^{2} = 1 \\ or \: \: \: \\ { \sin(e) }^{2} - 1 = { \cos(e) }^{2} \\ \cos(e) = \: \sqrt{ { \sin(e) }^{2} - 1 }$

now ,

taking RHS

and using identities,

$\frac{ \sin(e) }{ \sqrt{ { \sin(e) }^{2} - 1 } } \\ = \frac{ \sin(e) }{ \cos(e) } = \tan(e)$