Question

prove this please it's urgent​

Answer 1

Answer:

Here you go!

This is the proof

Answer 2

Answer:

Step-by-step explanation:

Let z = |x + iy|

| z | = √(x² + y²)

L.H.S:

|x - iy| / |-x + iy|

= | x + i (-y) | / | -x + iy|

= √ {x² + (-y)²} / √[(-x)² + y²]

= √(x² + y²) / √(x² +y²)

= 1

= R.H.S

Hence proved.