Question

prove this problem of trigonometry 2 please​

Answer 1

Answer:

$sqrt$

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Answer 2

Answer:

$4 \cos(x) \cos(x + \frac{\pi}{3} ) + \cos {}^{2} ( \frac{\pi}{3} ) \\ \\ = 4 \cos(x) ( \cos(x) \cos( \frac{\pi}{3} ) - \sin(x) \sin(\frac{\pi}{3} ) ) + \cos {}^{2} (\frac{\pi}{3} ) \\ \\ since \: \: \cos(\frac{\pi}{3} ) = \frac{1}{2} \\ \\ = 4 \cos(x) ( \frac{1}{2} \cos(x) - \frac{ \sqrt{3} }{2} \sin(x) ) + \frac{1}{4} \\ \\ = 2 \cos{}^{2} x - 2 \sqrt{3} \sin(x) + \frac{1}{4}$

Which isn't same

So may be there is some misprint in question