Math, asked by rajibiju, 10 months ago

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Answered by sandy1816

2

Step-by-step explanation:

secA+tanA-1/tanA-secA+1

=secA+tanA-(sec²A-tan²A)/tanA-secA+1

=(secA+tanA)(1-secA+tanA)/ tanA-secA+1

=secA+tanA

=1/cosA+sinA/cosA

=1+sinA/cosA

=(1+sinA)(1-sinA)/cosA(1-sinA)

=1-sin²A/cosA(1-sinA)

=cos²A/cosA(1-sinA)

=cosA/1-sinA

thankyou

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