Math, asked by prashantmallick, 1 year ago

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Answered by rohitkumargupta
10
HELLO DEAR,

cosA - sinA / cosA + sinA = sec2A - tan2A

⇒[ (cosA - sinA )/(cosA + sinA ] * (cosA - sinA)/(cosA - sinA)

⇒[ (cosA - sinA)² / (COS²A - sin²A) ]

⇒[ (cos²A + sin²A - 2sinAcosA) / (cos²A - sin²A) ]

⇒ [ 1 - sin2A ] / [ (1 - sin²A) - sin²A) ]
∴ [ 2sinФcosФ = sin2Ф ]

⇒[ 1 - sin2A ] / (1 - 2sin²A)

⇒1/(cos2A) - sin2A / cos2A
∴ [ 1 - 2sin²A = cos2A ]

⇒sec2A - tan2A

I HOPE ITS HELP YOU DEAR,
THANKS
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