prove this question in trigonometry
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Left side →sec4x−sec2x
=1/cos4x−1/cos2x
=1−cos2x/cos4x
=sin2x/cos4x
=tan2x(1/cos2x)
Apply the trig identity: 1/cos2x=(1+tan2x), we get:
Left side →tan2x(1+tan2x)=tan4x+tan2x.
I hope you liked it
here 2x means ^2x
=1/cos4x−1/cos2x
=1−cos2x/cos4x
=sin2x/cos4x
=tan2x(1/cos2x)
Apply the trig identity: 1/cos2x=(1+tan2x), we get:
Left side →tan2x(1+tan2x)=tan4x+tan2x.
I hope you liked it
here 2x means ^2x
ag0346810oxrqzo:
have u taken LCM in third line?
i got it
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