prove this question it's from icse R K Bansal book stage 3 q. 131 from trigonometry.
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SinA. Cos(90-A).cosA/sin(90-A) +cosA.sin(90-A).sinA/cos(90-A)
=sinA.sinA.cosA/cosA + cosA.cosA.sinA/sinA
=sin²A + cos²A
= 1
=sinA.sinA.cosA/cosA + cosA.cosA.sinA/sinA
=sin²A + cos²A
= 1
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Hi friend,
We have to know ,
Sin (90°- θ)= cosθ
Cos (90°-θ) = sinθ
Sub.in the given equation,it becomes ,
Sin²θ + cos²θ it becomes 1.
We know that
Sin²θ + cos²θ= 1.
:- the answer is 1.
Hope this helped you a little!!!!
We have to know ,
Sin (90°- θ)= cosθ
Cos (90°-θ) = sinθ
Sub.in the given equation,it becomes ,
Sin²θ + cos²θ it becomes 1.
We know that
Sin²θ + cos²θ= 1.
:- the answer is 1.
Hope this helped you a little!!!!
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