Question

prove this question of class 11th. ​

Answer 1

Answer:

im in 7th sórry

Answer 2

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To solve :-

$\frac{tan (\frac{3\pi}{4} + θ) - tan( \frac{3\pi}{4} - θ)}{(cot( \frac{3\pi}{4} - θ) - cot( \frac{3\pi}{4} + θ))tan (\frac{3\pi}{4} + θ) tan( \frac{3\pi}{4} - θ) }$

Solution:-

$let \: \frac{3\pi}{4} + θ = x \: and \: \frac{3\pi}{4} - θ \: = y$

$\frac{tan (\frac{3\pi}{4} + θ) - tan( \frac{3\pi}{4} - θ)}{(cot( \frac{3\pi}{4} - θ) - cot( \frac{3\pi}{4} + θ))tan (\frac{3\pi}{4} + θ) tan( \frac{3\pi}{4} - θ) } \\ can \: be \: now \: rewritten \: as \:$

$\frac{tanx - tany}{(coty - cotx)tanx \times tany} \\ = \frac{tanx - tany}{( \frac{1}{tany} - \frac{1}{tany} )tanx \: tany} \\ = \frac{tanx - tany}{ \frac{(tanx - tany)}{tanx \: tany} \times tanx \: tany}$

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