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In the given figure ADEF is //gm therefore , FE//AD and DE//AF
1) FE // AD , also FE //AB
using BPT
(CE/BE) = (CF/FA)--------------(I)
2) ED//AF , also ED//AC
Using BPT
(BE/EC) = (BD/AD)----------------(ii)
From (I) and (ii)
(CE/BE) = (AD/BD) (proved)
1) FE // AD , also FE //AB
using BPT
(CE/BE) = (CF/FA)--------------(I)
2) ED//AF , also ED//AC
Using BPT
(BE/EC) = (BD/AD)----------------(ii)
From (I) and (ii)
(CE/BE) = (AD/BD) (proved)
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