Prove this
tan4teetha + tan(square)teetha = sec4teetha - sec4teetha.
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Answered by
2
your answer is in the ATTACHMENT
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Attachments:
Answered by
1
Step-by-step explanation:
To prove: tan⁴θ + tan²θ = sec⁴θ - sec²θ
LHS = tan²θ(1 + tan²θ)
= tan²θ × sec²θ
RHS = sec²θ(sec²θ - 1)
= sec²θ × tan²θ
LHS = RHS
Hence proved
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