Question

prove this trigonometric equation​

Answer 1

Answer:

LHS: (sec Θ+ cosΘ)(sec Θ+cos Θ)

=$sec^{2} O+cos^{2} O+2secOcosO$

(using (a+b)(a+b) identity)

=$sec^{2} O+cos^{2}$+2

(as secΘcosΘ=1)

=$1+tan^{2}O -1+sin^{2} O$

=tan2Θ+sec2Θ

=RHS