Prove this.......
Urgent!!!!
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Answered by
2
LHS ,
= (1+cot²A)(1+tan²A)
= cosec²A × sec²A
= 1/sin²A × 1/cos² A
= 1/sin²A × 1/(1-sin²A)
= 1/sin²A - sin⁴A.
= RHS.
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@spyder
Answered by
1
Hence it is proved that ( 1 + 1/tan²A ) ( 1 + 1/cot²A ) = 1/( sin²A - sin^4A )
To prove,
( 1 + 1/tan²A ) ( 1 + 1/cot²A ) = 1/( sin²A - sin^4A )
LHS:
= ( 1 + 1/tan²A ) ( 1 + 1/cot²A )
wkt tanA = 1/cotA and vice versa
= ( 1 + cot²A ) ( 1 + tan²A )
= cosec²A × sec²A
= 1/sin²A × 1/cos²A
wkt cos²A + sin²A = 1
= 1/sin²A × 1/(1-sin²A)
= 1/sin²A(1-sin²A)
= 1/( sin²A - sin^4A )
:RHS
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