Prove thst A(-1,-2),B(1,0)C(-1,2) D(-3,0)are the vertices of a square
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Answer:
Given points are
A(−2,−1),B(1,0),C(4,3) and D(1,2)
A quadrilateral is a parallelogram if the opposite sides are equal.
∴AB
2
=(−2−1)
2
+(−1−0)
2
=9+1
=10
BC
2
=(4−1)
2
+(3−0)
2
=9+9
=18
CD
2
=(1−4)
2
+(2−3)
2
9+1
=10
AD
2
=(−2−1)
2
+(−1−2)
2
=9+9
=18
∴AB=CD=
10
and BC=AD=
18
∴ The opposite sides of the quadrilateral ABCD are equal, the four points from a parallelogram.
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