prove tht :cot(90-theta) / tan theta + cosec(90-theta)sin theta / tan(90-theta) =sec^2 theta.
Answers
Answered by
30
L.H.S cot(90-x)/tanx +cosec(90-x)sinx/tan(90-x) =tanx/tanx + secxsinx/cotx = 1 + 1/cosx.sinx.sinx/cosx =1 + sin square x/cos squarex =cos square x + sin square x/ cos square x = 1/cos square x = sec square x_ RHS
sahilmalik82:
is there anything else
Answered by
79
Hope this helps..!
# Be Brainly...
Attachments:
Similar questions