Question

prove triangle ced is equilateral triangle

Answer 1

Answer:

Step-by-step explanation:

Hello Mate!

Error correction : It will be "show that ∆ADE ~ ∆BCE"

Given : ∆CDE is equilateral ∆ on side CD of square ABCD.

To prove : ∆ADE ~ ∆BCE.

Proof : In ∆ADE and ∆BCE

Since sides of square are equal

AD = BC _(i)

Since side of equilateral ∆ are equal

DE = CE _(ii)

Now, < ADC = < BCD = 90°

< CDE = < DCE = 60°

Adding borh equation we get,

< ADE = BCE = 150° _(iii)

Hence by (i), (ii) and (iii) we prove that,

∆ADE ~ BCE ( by SAS congruency )

Therefore, ar(∆ADE) = ar(∆BCE)