prove tthe following
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Step-by-step explanation:
1+cosA+sinA/1+cosA-sinA
devide cosA in both numerator & denominator
=secA+1+tanA/secA+1-tanA
=(secA+tanA)+(sec²A-tan²A)/ secA-tanA+1
=(secA+tanA)+(secA+tanA)(secA-tanA)/ (secA-tanA+1)
=(secA+tanA)(1+secA+tanA)/ secA-tanA+1
=secA+tanA
=1/cosA+sinA/cosA
=1+sinA/cosA
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