Question

prove tthe following ​

Answer 1

Step-by-step explanation:

1+cosA+sinA/1+cosA-sinA

devide cosA in both numerator & denominator

=secA+1+tanA/secA+1-tanA

=(secA+tanA)+(sec²A-tan²A)/ secA-tanA+1

=(secA+tanA)+(secA+tanA)(secA-tanA)/ (secA-tanA+1)

=(secA+tanA)(1+secA+tanA)/ secA-tanA+1

=secA+tanA

=1/cosA+sinA/cosA

=1+sinA/cosA

Answer 2

Answer:

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