prove under root 1+sin0/1-sin0=sec0+tan0
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√[(1+sina)/(1-sina)]
= √[(1+sina)(1+sina)/(1-sina)(1+sina)]
=√[(1+sina)²/(1-sin²a)]
=√[(1+sina)²/cos²a]
=(1+sina)/cosa
=1/cosa. +sina/cosa
=seca+tana
proved.✌✌✌✌✌✌✌✌✌
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