prove under root of 2 is irrational number
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Hii friend,
To prove : ✓2 is irrational Number
Proof :- If possible , let ✓2 be rational Number and let it's simplest form be a/b .
Then , a and b are integers having no Common factor other than 1.
Now,
✓2 = a/b
2 = a²/b². [ On squaring both sides]
2b² = a².........(1)
2 divides a²
Therefore,
2 divides a
Let a = 2C.
Putting a= 2C ,in equation (1)
2b² = a²
2b² = (2C)²
2b² = 4C²
b² =4C²/2
b² = 2C²
2 Divides b² => 2 Divides b .
Thus,
2 is a common factor of a and b.
But , this contradicts the fact that a and b have no Common factor other than 1.
This contradiction arises by assuming that ✓2 is rational.
Hence,
✓2 is irrational Number..... PROVED........
HOPE IT WILL HELP YOU...... :-)
To prove : ✓2 is irrational Number
Proof :- If possible , let ✓2 be rational Number and let it's simplest form be a/b .
Then , a and b are integers having no Common factor other than 1.
Now,
✓2 = a/b
2 = a²/b². [ On squaring both sides]
2b² = a².........(1)
2 divides a²
Therefore,
2 divides a
Let a = 2C.
Putting a= 2C ,in equation (1)
2b² = a²
2b² = (2C)²
2b² = 4C²
b² =4C²/2
b² = 2C²
2 Divides b² => 2 Divides b .
Thus,
2 is a common factor of a and b.
But , this contradicts the fact that a and b have no Common factor other than 1.
This contradiction arises by assuming that ✓2 is rational.
Hence,
✓2 is irrational Number..... PROVED........
HOPE IT WILL HELP YOU...... :-)
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