Prove using boolean laws
xy + x'z + xz = xy + x'z
Answers
Answer:
Firstly I think that the question provided isn't correct...so by slightly modifying the LHS i came to the following conclusion:-
By recognizing that this is just the Consensus Theorem, observe that:
xy+x′z+yz
=xy+x′z+(1)yz
=xy+x′z+(x+x′)yz
=xy+x′z+(xyz+x′yz)
=(xy+xyz)+(x′z+x′yz)
=xy(1+z)+x′z(1+y)
=xy(1)+x′z(1)
=xy+x′z
Hope that helped....do pardon if the question provided above is correct...THANKYOU
Explanation:
Laws of Boolean Algebra
Boolean Algebra uses a set of Laws and Rules to define the operation of a digital logic circuit
As well as the logic symbols “0” and “1” being used to represent a digital input or output, we can also use them as constants for a permanently “Open” or “Closed” circuit or contact respectively.
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A set of rules or Laws of Boolean Algebra expressions have been invented to help reduce the number of logic gates needed to perform a particular logic operation resulting in a list of functions or theorems known commonly as the Laws of Boolean Algebra.