Prove using pm1 : 12 n+25 n-1 is divisible by 13, n∑n
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25k+1+4k+13k+112=25⋅25k+124k3k1225k+1+4k+13k+112=25⋅25k+124k3k12
=13⋅25k+12⋅25k+124k3k12=13⋅25k+12⋅25k+124k3k12
=13⋅25k+12(25k+4k3k12)
=13⋅25k+12⋅25k+124k3k12=13⋅25k+12⋅25k+124k3k12
=13⋅25k+12(25k+4k3k12)
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