Question

prove, v=u+at using dimension formula?​

Answer 1

$\huge \pink{To \: PrOvE}$

$\bf{v = u + at}$

$\huge\green\bigstar \red{SoLuTioN}$

equation is v=u+at

• dimensional formula of v=(M°LT^-1)
• dimensional formula of u=(M°LT^-1)
• dimensional formula of a=(M°LT^-2)
• dimensional formula of t=(M°L°T)

LHS is the dimensional formula of v=(M°LT^-1)

RHS=dimensional formula of u+dimensional formula of a×dimensional formula of t

=(M°LT^-1)+(M°LT^-2)×(M°L°T)

=(M°LT^-1)+(M°LT^-1)

=2(M°LT^-1)

2 is a dimensionless constant ,therefore LHS=RHS

Hence,the given relationship(equation)is dimensionally correct.

$<marquee scrollamount = 600>$

$\huge \fbox \pink \star \purple{k047}$

Answer 2

Answer:

• a =dv/dt
• dv= a. dt
• Integration dv (avg. V to u ) = int. (avg. 0 to t ) a. dt
• V - u = a(t-0)
• V = u + at

May it correct. .

Plzz i want brainlist. . .

Followup guys. .