Question

prove vav=u+v/2 answer ​

Answer 1

Answer:

If the velocity were u , ( with no change) distance would be u t for a time t

If the velocity were v , ( with no change) distance would be v t for a time t ,

If the velocity changes uniformly , from u to v in a time t then the distance is

Area of rectangle ut and the area of triangle

( 1/2) ( v-u) t

Adding we get s = (u+ v)t / 2

Step-by-step explanation:

Whenever a quantity changes uniformly, the average value of the quantity is half of the sum of the initial and final value .

When velocity changes uniformly, distance is average velocity * time .

Average velocity is ( u + v)/2

So distance is ( u + v) t /2 .

Answer 2

Answer:

See the attachment. hope it helps you