Prove when A=B in Sin(A+B)
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Answered by
1
Answer:
sin(A+B)=sinAcosB+cosAsinB
Step-by-step explanation:
we know that A=B. then sinAcosA+cosAsinA and we also know that sinA=1/cosA then sinA×1/sinA+cosA×1/sinA= 1+1=2
Answered by
1
Answer:
Answer:
sin(A+B)=sinAcosB+cosAsinB
Step-by-step explanation:
we know that A=B. then sinAcosA+cosAsinA and we also know that sinA=1/cosA then sinA×1/sinA+cosA×1/sinA= 1+1=2
Step-by-step explanation:
Hope this answer will help you.✌️
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