Math, asked by jagtarchannu, 6 months ago

prove why squareroot 7 is an irrational number

Answers

Answered by sravan1487

Answer:

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Step-by-step explanation:

Let's prove it by contradiction method. Assume that √7 is a rational number. From this we can conclude that a^2 is divisible by 7 and thus a is also divisible by 7. ... So, our assumption that √7 is rationalis wrong and thus √7 is an irrational number.

Answered by karthikkosuri2005

Step-by-step explanation:

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