prove with explanation theta -
>0(lim). sin theta/theta =1
Points :-15☺
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Answered by
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Lim(∅→0) sin∅/∅ =1
this can be proved by using expansion of sinx
sinx = x -x³/3! + x^5/5! -x^7/7 +........∞
use this in limit
Lim(∅→0)[∅ -∅³/3! +∅^5/5! -∅^7/7! +...∞]/∅
Lim(∅→0) [1 -∅²/3! +∅⁴/5! +∅^6/7!+..∞]
now put ∅ =0 to check limit you can see limit gain finite value e.g 1
so, Lim(∅→0) sin∅/∅ = 1
★★★hence proved★★★
this can be proved by using expansion of sinx
sinx = x -x³/3! + x^5/5! -x^7/7 +........∞
use this in limit
Lim(∅→0)[∅ -∅³/3! +∅^5/5! -∅^7/7! +...∞]/∅
Lim(∅→0) [1 -∅²/3! +∅⁴/5! +∅^6/7!+..∞]
now put ∅ =0 to check limit you can see limit gain finite value e.g 1
so, Lim(∅→0) sin∅/∅ = 1
★★★hence proved★★★
Answered by
2
Answer:
Hence this is proved so it helps u
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