Question

prove with simple method
I will mark as brainiest​

Answer 1

heya your answer is here... hope it helps

Answer 2

Answer:

I am taking Ф as A

Step-by-step explanation:

= $\frac{sinA}{1-cosA}  + \frac{tanA}{1+cosA}$

on adding

= $\frac{(cosA + sinA)(sinA)}{(sinA)(sinA)(cosA)}$    (by 1st identity)

=taking sinA common in numerator

= $\frac{sinA+tanA}{1-cos^{2}A }$

=> In numerator convert tanA into $\frac{sinA}{cosA}$

we get

= $\frac{(cosA + 1)[sinA]}{(sin^{2}A)(cosA)}$

= $\frac{(cosA + 1)}{(sinA)(cosA)}$

= $\frac{(1)}{(sinA)(cosA)}$ + $\frac{(1)}{(cosA)}$

hence we get

= cosecA . secA + cotA