Prove X is irrational if . X^2=0.256
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Let x be a real number. We want to prove by contradiction that if is irrational, then x is irrational.
Proof: Assume the negation of this statement: is irrational and x is rational.
(Keep in mind that the negation of an implication, is ).
But if x is rational, then x can be written as where b and c are integers.
Then which is also rational.
This contradicts the statement that is irrational.
Thus, if if is irrational, then x is irrational.
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