Prove x = α +β+ γ ( using figure given )
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In the given figure, We have at a point ∠x
Because at a given point, angle measures to be 360°.
∴ Other angle = 360° - x
Now, In the enclosed figure ( which is also a quadrilateral because It has four sides. )
We know,
⇒ Sum of all interior angles of a Quadrilateral = 360°
⇒ ɑ + β + Ɣ + (360° - x) = 360°
⇒ ɑ + β + Ɣ - x = 360° - 360°
⇒ ɑ + β + Ɣ - x = 0
⇒ ɑ + β + Ɣ = x
Hence, Proved.
Some Information :-
☛ The sum of all interior angles of a triangle is 180° while the sum of all interior angles of a quadrilateral is 360°.
☛ A quadrilateral is closed figure enclosed by four sides.
Square, Rectangle, Rhombus, are some examples of a quadrilateral.
☛ A point in a given plane measures 360°.
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Because at a given point, angle measures to be 360°. Now, In the enclosed figure ( which is also a quadrilateral because It has four sides. ) Hence, Proved. ☛ The sum of all interior angles of a triangle is 180° while the sum of all interior angles of a quadrilateral is 360°.
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