Math, asked by officialmrxyt, 1 month ago

Prove- (xa/xb)*a+b. x(xb/xc)b+c x(xc/xa)c+a =1​

Answers

Answered by suhani5339
1

Step-by-step explanation:

Replacing c with n for easy typing

(xª/xb)(a+b) * (xb/xn)(b+n) * (xn/xª)(n+a)

= (xa-b)(a+b) + (x(b-nl/b+n) (xn_a)(n+a) * = x(a2-b²) * x(b2-n2) *

x(n²-a2) n2-a2) = x(a2-b2 + b2-n² +

= xº

= 1

(xª/xb)(a+b) = (xb/xn)(b+n) * {x^/x²){n+a) = 1

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