Prove- (xa/xb)*a+b. x(xb/xc)b+c x(xc/xa)c+a =1
Answers
Answered by
1
Step-by-step explanation:
Replacing c with n for easy typing
(xª/xb)(a+b) * (xb/xn)(b+n) * (xn/xª)(n+a)
= (xa-b)(a+b) + (x(b-nl/b+n) (xn_a)(n+a) * = x(a2-b²) * x(b2-n2) *
x(n²-a2) n2-a2) = x(a2-b2 + b2-n² +
= xº
= 1
(xª/xb)(a+b) = (xb/xn)(b+n) * {x^/x²){n+a) = 1
Similar questions