Question

prove xcube +ycube+zcube-3xyz=(x+y+z)(x-y)whole square +(y-z)square+(z-x)square
help fast​

Answer 1

L.h.s= x³ + y³ + z³- 3xyz

= ( x+y+z) (x²+y²+z²-xy-yz-zx)

= 1/2(x+y+z)(2x²+2y²+2z²-2xy-2yz-2zx)

= 1/2 ( x+y+z) {x²-2xy+y² +y² -2yz+z²+z²-2zx+x²)

= 1/2 ( x + y+z) {( x-y)²+(y-z)² +(z-x)²}

* I think u must write 1/2 in the rhs

plz mark it as brainliest!