Question

Prove ZA + ZB = 2 ZCOD
The diagonals of a rectangle ABCD intersect at 0. If ZAOB = 30°, find ZCOD and ZOCD

Answer 1

Answer:

Answer

From figure,

∠COD=∠AOB (Vertically opposite angles)

=>∠COD=30

o

In △OCD,

∠OCD+∠ODC+∠COD=180

o

∠OCD+∠OCD+∠COD=180

o

(Diagonals are equal in rectangle)

2∠OCD+30

o

=180

o

∠OCD=75

o