Question

.................proved..............​

Answer 1

《《《 holla dued your answer is ______________________________below .....》》》》

THALES THM ::: IF A LINE IS DRAWN PARALLEL TO ONE SIDE OF A TRIANGLE , THEN IT CUTS INTO TWO SIDES PROPORTANALLY...

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TO PROVE = DE / BC = AE/ AC = AD/AB.

Proof ::

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if a line intersects sides AB and AC of a triangle ABC at D and E respectively , and also llel to BC ,

You know that DE ll BC

thn in triangle ABC and Triangle ADE

angle A = angle A { common angles }

angle ADE = angle ABC { BC ll DE}

angle AED = angle ACB { BC ll DE }

therefore : triangle ABC is congruent to triangle ADE .

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now in similar triangle....

AD / AB = AE / AC = DE / BC.

HENCE PROVED...

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1. HAVE A GOOD DAY....✌✌

Answer 2

xD wht do u wan't now..


abe oye ye ky answer post kiya h mere question pr...

?????