proved s.t.p volume of gas in 22.4 liter?
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pressure in stock is 1 atm or (1.13025×10^5) Pascal
temperature =273.15 Kelvin
and when we use ideal gas eqn. pv= nrt
for 1 mole of gas by putting the value of pressure and temperature and universal gas constant as 0.0821 atm litre we will get the volume = 22.4256 litre
temperature =273.15 Kelvin
and when we use ideal gas eqn. pv= nrt
for 1 mole of gas by putting the value of pressure and temperature and universal gas constant as 0.0821 atm litre we will get the volume = 22.4256 litre
Answered by
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The Molar Volume of a gas at STP is a constant using Avogadro's value of 22.4 L/mol.
To calculate this we can use the Ideal gas law of PV=nRT
At STP (Standard Temperature and Pressure)
P = 1 atm
V = ?
n = 1 mol
R = 0.0821 atmLmolK
T = 273 K
(1atm)(V)=(1mol)(0.0821atmLmolK)(273K)
V=(1mol)(0.0821atmLmolK)273K1atm
V=22.4L
This is the volume of one mole of gas at STP.
I hope this was helpful.
To calculate this we can use the Ideal gas law of PV=nRT
At STP (Standard Temperature and Pressure)
P = 1 atm
V = ?
n = 1 mol
R = 0.0821 atmLmolK
T = 273 K
(1atm)(V)=(1mol)(0.0821atmLmolK)(273K)
V=(1mol)(0.0821atmLmolK)273K1atm
V=22.4L
This is the volume of one mole of gas at STP.
I hope this was helpful.
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