Question

Proved that, Energy density=1/2×stress×strain​

Answer 1

Answer:

Let the length of wire be increased by l by applying a force F. Average internal force, = (0 + F)/2 = F/2 Work done = F/2 x l The work done is stored as potential energy ⇒ Elastic Potential energy = Fl/2 = 1/2(F/A)(l/L). x (A.L) where A = cross-sectional area L = length E.P.E = 1/2 x stress x strain x volume of wire Energy density = {E.P.E./Volume of the wire} = 1/2 x stress x strainRead more on Sarthaks.com - https://www.sarthaks.com/561163/prove-that-elastic-potential-energy-density-stretched-wire-equal-product-stress-strain